Calculate the entropy change of the system
Favorites|Homepage
Subscriptions | sitemap
HOME > > Calculate the entropy change of the system

Calculate the entropy change of the system

[From: ] [author: ] [Date: 12-05-11] [Hit: ]
so that 0°C is the equilibrium melting point of water.At the melting point, the solid and liquid phases are in equilibrium,is zero.The enthalpy change for the above reaction is simply the negative of the enthalpy of fusion,ΔG = 0 = ΔH - T*ΔS = (-6,......
Calculate the entropy change of the system when 2.00 mol of water freezes to form ice at 0 °C, given that ΔfusH°(H2O) = +6.02 kJ mol–1.

-
I assume the system is at 1 bar pressure, so that 0°C is the equilibrium melting point of water.

At the melting point, the solid and liquid phases are in equilibrium, so the Gibbs free energy change for the reaction:

H2O(l) -> H2O(s)

is zero.

The enthalpy change for the above reaction is simply the negative of the enthalpy of fusion, so we have that:

ΔG = 0 = ΔH - T*ΔS = (-6,020 J/mol) - (273.15K)*ΔS

ΔS = -(6,020 J/mol)/(273.15K) = -22.04 J/(K*mol)

In this case, we have two moles of water freezing, so the entropy change of the system is twice the per-mole value, or -44.08 J/K
1
keywords: Calculate,system,change,the,of,entropy,Calculate the entropy change of the system
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .