Use the thermochemical equations shown below to determine
the enthalpy for the reaction:
H2SO4(l)=>H2S(g) + 2O2(g)
SO3(g) + H2O(g)=>H2SO4(l) H=-251.1KJ
H2S(g) + 2O2(g)=>SO3(g) + H2O(l) H=-845.2KJ
H2O(l)=>H2O(g) H=134.8KJ
I put 961.5KJ but it's wrong, explain please
the enthalpy for the reaction:
H2SO4(l)=>H2S(g) + 2O2(g)
SO3(g) + H2O(g)=>H2SO4(l) H=-251.1KJ
H2S(g) + 2O2(g)=>SO3(g) + H2O(l) H=-845.2KJ
H2O(l)=>H2O(g) H=134.8KJ
I put 961.5KJ but it's wrong, explain please
-
H2SO4(l) => SO3(g) + H2O(g) H=+251.1KJ
SO3(g) + H2O(l) => H2S(g) + 2O2(g)= H=+845.2KJ
H2O(g)=>H2O(l) H=-134.8KJ
I get 961.5 as well. Round if off to 962??? Also, it could be a data entry error in whatever you are using (like a computer-based system or a printing error in an answer in your textbook.) In any event, you did the problem did the problem correctly, I think, in my status as just some guy on the Internet, that ice cream is the right choice at this moment in your life.
More Hess' Law:
http://www.chemteam.info/Thermochem/Ther…
SO3(g) + H2O(l) => H2S(g) + 2O2(g)= H=+845.2KJ
H2O(g)=>H2O(l) H=-134.8KJ
I get 961.5 as well. Round if off to 962??? Also, it could be a data entry error in whatever you are using (like a computer-based system or a printing error in an answer in your textbook.) In any event, you did the problem did the problem correctly, I think, in my status as just some guy on the Internet, that ice cream is the right choice at this moment in your life.
More Hess' Law:
http://www.chemteam.info/Thermochem/Ther…