I am calculating the molarity of permanganate as follows:
M of MnO4 = (V of Fe2+)(M of Fe2+)/5 (V of MnO4)
Molarity of iron (II) is given as 0.1 M. With my data, these are my calculations:
M of MnO4 = (.01009L)(0.1M) / 5(.01219L)
M of MnO4 = 0.01656
But would the answer be 0.01656 or 0.02, since there's 1 sig fig for iron (II)'s molarity?
M of MnO4 = (V of Fe2+)(M of Fe2+)/5 (V of MnO4)
Molarity of iron (II) is given as 0.1 M. With my data, these are my calculations:
M of MnO4 = (.01009L)(0.1M) / 5(.01219L)
M of MnO4 = 0.01656
But would the answer be 0.01656 or 0.02, since there's 1 sig fig for iron (II)'s molarity?
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The rules for sig fig says only 1 digit allowed so 0.2, but it is strange that you'd be given 4 digits for volume (0.01009-L and 0.01219-L)
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you should look up the division for sig.figs. but it should be the amount of sig figs you started with . the one that has the least.
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You're right about the one sig fig, so .02.