in a bag there are 5 red marbles, 2 green, 4 yellow, 3 blue. once marble is drawn, it is not replaced. find the propability outcome of each.
1. two green marbles in a row?
2. 2 red marbles in a row?
3. a red marble, a green marble, and then a blue marble?
4. 3 yellow marbles in a row?
5. ared and then a yellow marble?
6.a green and then a blue marble?
1. two green marbles in a row?
2. 2 red marbles in a row?
3. a red marble, a green marble, and then a blue marble?
4. 3 yellow marbles in a row?
5. ared and then a yellow marble?
6.a green and then a blue marble?
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1. Dependent since the probability of the second green marble depends on whether or not you got a green marble the first time. You start with 2 greens out of 14 total marbles. After you get a green the first time (we don't care about if you don't get a green the first time because then it doesn't matter if you get a green the second time) you have 1 green out of 13 total marbles
P(green) * P(green) = 2/14 * 1/13 = 1/91
2. Also dependent
P(red) * P(red) = 5/14 * 4/13 = 10/91
3. Still dependent
P(red)*P(green)*P(blue) = 5/14 * 2/13 * 3/12 = 5/182
4. P(yellow)*P(yellow)*P(yellow) = 4/14 * 3/13 * 2/12 = I think you should get it by now
P(green) * P(green) = 2/14 * 1/13 = 1/91
2. Also dependent
P(red) * P(red) = 5/14 * 4/13 = 10/91
3. Still dependent
P(red)*P(green)*P(blue) = 5/14 * 2/13 * 3/12 = 5/182
4. P(yellow)*P(yellow)*P(yellow) = 4/14 * 3/13 * 2/12 = I think you should get it by now