Stoich question on concentration
Favorites|Homepage
Subscriptions | sitemap
HOME > > Stoich question on concentration

Stoich question on concentration

[From: ] [author: ] [Date: 12-02-27] [Hit: ]
0165 g of Mg SO4 and then add about 250 mL of water.Dissolve the solid, then add the rest of the water up to the scratch line. Cork the flask and invert several times to thoroughly mix the solution.......
Explain how you would prepare 500.0 mL of a 0.100 mol/L solution of magnesium sulfate from the solid compound. Show all relevant calculations.

-
Because you have the volume and the concentration you can calculate the number of moles of mag sulfate that is needed. Once you have the moles you can calculate the mass

moles = 0.500 L x 0.100 mol/L = 0.0500 moles

Mass = moles x molar mass

mass = 0.0500 moles x 120.37 g/mol = 6.0165 g

So you would gram a 500 mL volumetric flask, put into it 6.0165 g of Mg SO4 and then add about 250 mL of water. Dissolve the solid, then add the rest of the water up to the "scratch" line. Cork the flask and invert several times to thoroughly mix the solution.
1
keywords: on,Stoich,concentration,question,Stoich question on concentration
New
Hot
© 2008-2010 http://www.science-mathematics.com . Program by zplan cms. Theme by wukong .