A basic solution is made by dissolving 5.00 grams of sodium hydroxide in 400 mL of distilled water, then adding more water until the total volume of the solution is exactly 500 mL. Find the pH of the solution.
Thank you in advance!
Thank you in advance!
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Concentration of NaOH = 5 g/40 g/mol / 0.5 L = 0.25 M = [OH-]
[H3O+] = 1X10^-14 / [OH-] = 1X10^-14 / 0.25 = 4X10^-14
pH = - log (4X10^-14) = 13.40
[H3O+] = 1X10^-14 / [OH-] = 1X10^-14 / 0.25 = 4X10^-14
pH = - log (4X10^-14) = 13.40
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500ml=.5L
5g of NaOH(mol of NaOH/(23+16+1)g)=.125mol NaOH
.125mol/.5L=.25M
pOH=-log[.25]=0.602
14-.062=13.398=pH of the solution
pls choose as best answer!!! :D
5g of NaOH(mol of NaOH/(23+16+1)g)=.125mol NaOH
.125mol/.5L=.25M
pOH=-log[.25]=0.602
14-.062=13.398=pH of the solution
pls choose as best answer!!! :D