Please work everything out and explain.! Thanks
This equation might help. h= -16t^2 + vt + s
A person springs off a 12 foot high diving board with an initial velocity of 15 feet per second. How many seconds does it take the person to hit the water?
(I'm not sure if the 12 is supposed to be a negative in the equation or a positive and please work everything out step by step b/c i want to see if i had gotten the answer right.)
This equation might help. h= -16t^2 + vt + s
A person springs off a 12 foot high diving board with an initial velocity of 15 feet per second. How many seconds does it take the person to hit the water?
(I'm not sure if the 12 is supposed to be a negative in the equation or a positive and please work everything out step by step b/c i want to see if i had gotten the answer right.)
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h = -16t^2 + 15t + 12 (upward is positive)
hit water ---> h = 0 and solve for t >0
hit water ---> h = 0 and solve for t >0
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all i know is that vt is the velocity, which in this case is 15. also, s = height, which is 12. so the equation now is h = -16t^2 + 15t + 12. now, set h = 0 and solve. t = ___.
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12 is positive h = -16t^2 +15t +12 Hits water when h = 0
-16t^2 +15t +12 = 0 t >0 16t^2 -15t -12 = 0 t = [-(-15) +/- sq root( 15^2 -4(16)(-12)]/32
t = [12 +/- sq root 993]/32 x = [12 + 31.5119]/32 t = 1.35974 secs
-16t^2 +15t +12 = 0 t >0 16t^2 -15t -12 = 0 t = [-(-15) +/- sq root( 15^2 -4(16)(-12)]/32
t = [12 +/- sq root 993]/32 x = [12 + 31.5119]/32 t = 1.35974 secs