Someone please help with chemistry!!!!
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Someone please help with chemistry!!!!

[From: ] [author: ] [Date: 12-02-27] [Hit: ]
then, to calculate Ea.......
If the rate constant for a particular reaction doubles between 20 °C and 40 °C, calculate the value of the activation energy for the reaction.

a. 0.461 kJ
b. 0.231 kJ
c. 261 kJ
d. 26.4 kJ
e. 52.9 kJ

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You'll use the Arrhenius equation to calculate Ea.

The equation is:

ln(k2/k1) = -Ea/R(1/T2 - 1/T1)

Since you want the rate to double, k2 will be 2k1, so the ratio of k2/k1 = 2. Also, remember that you must convert your temperatures into Kelvin before using them in the equation, and R will have a value of 8.314 J/mol K. It's a simple matter, then, to calculate Ea.
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