Please help with the magnitude of charge (algebra physic)

Two 2-g pith balls hang in air on essentially weightless cotton threads 50-cm long from a common point of support. The balls are then equally charged and they spring apart, each making an angle of 10° with vertical. Find the magnitude of the charge on each ball.

I cant get the right answer. THE ANSWER IS 0.11 uC, please show me the steps

I already posted the instructions in my previous answer (see link). Let me do the arithmetic for you:

Step1 Find the weight of each ball in newtons (W=mg)
W = 0.002x9.81
= 0.01962N

Step 2 Find the tension in each thread using Tcos(10°) = W
Tcos(10°) = 0.01962
T = 0.01962/cos((10°)
= 0.01992N

Step 3
The electrostatic repulsion force, F on each charge = Tsin(10°) because the balls are in equilibrium.
F = 0.01992sin(10°)
= 3.46x10^-3N

Step 4
Use F = kq1q2/d² = kq²/d² to find q

From a suitable diagram you will see the distance of each ball from the centre line = 0.5sin(10°) = 0.0868m.
So the distance between the balls is 2 x0.0868 = 0.174m

3.46x10^-3 = 9x10^9 x q² /0.174²
q² = 1.16x10^-14
q = 1.1x10^-7C
= 0.11uC

Do you have any exams on this material?> If so, you need to go through the working in detail and make sure you understand every line. Make sure you get the same values when you try it for yourself using your calculator.