Guys, is this right? 6 HCl + 2 Al -> AlCl + 3H(subscript)2

also this one: 6 HOAc + 2 Al -> Al(OAc) + 3 H(sbuscript)2?

Nope, to balance equations the number of reactants must be the same on both sides of the '->'

So, HCL + AL -> AlCl + H(sub)2

You would first add a 2 to the HCL to get same num,ber of hydrogen, then add a 2 infront of AlCl to get same number of Cl, and finaly a 2 infront of the Al to get same number of aluminum

2HCl + 2 Al --> 2AlCl + H(sub)2 i belive.


For second one
you may have some typo or somethng, but i dont recall any element with the name Ac at that level of chemestry, Sorry

You gotta count how many atoms of each element you have if they aren't the same on each side then your wrong you have 2 aluminum on the left but one on the right 6cl to 1 for the first one...second one doesn't look close either

no not at all the hydrogen is good but you have 6 Cl on one side and one on the other. the answer is 2HCL + 2Al -> 2AlCl + H2

Way off