A mole of pop cans stacked on top of each other to the sun
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A mole of pop cans stacked on top of each other to the sun

[From: ] [author: ] [Date: 11-12-30] [Hit: ]
02x10^23cans)(4.75inches/1 can)(2.54cm/1 inch)(10^-5cm/1cm)(distance/150,000,000) = 4.8x10^12-6.......
How many times would a mole of pop cans stacked on top of each other reach from the earth to the sun and back.

1 can = 4.75 inches
distance = 150,000,000km
is this right? (6.02x10^23cans)(4.75inches/1 can)(2.54cm/1 inch)(10^-5cm/1cm)(distance/150,000,000) = 4.8x10^12

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6.02 * 10^23 cans * [ 4.75 inches / 1 can]* [2.54 cm / 1 inch] * [ 1 m / 100 cm ] * [1 km / 1000 m] * [Number of times to the sun / 150 000 000 km] * [number of round trips / 2 times to the sun] = 2.42 * 10^11 round trips to the sun and back..

We are disagreeing by a factor of 10. I don't know why.

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distance in cm = 1.5x10E8 km x 10E3m/km x 10E2cm/m = 1.5x10E13 cm
length of 1 mol cans = 6.02x10E23cansx4.75 in/can x 2.54 cm/in = 7.26x10E24

Round trip = 2 x 1.5x10E13 = 3.0x10E13
# round trips = 7.26x10E24/3.0x10E13 = 2.4x10E11 round trips
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