What volume of 1.50 mol/L H2S will neutralize a solution containing 32.0g NaOH?
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Equation:
2NaOH + H2S → Na2S + 2H2O
2mol NaOH react with 1 mol H2S
Molar mass NaOH = 40g/mol
32.0g NaOH = 32/40 = 0.80 mol NaOH
This will react with 0.40 mol H2S
1000mL H2S solution = 1.5 mol H2S
volume that contains 0.4 mol H2S = 1000/1.5*0.4 = 267mL
2NaOH + H2S → Na2S + 2H2O
2mol NaOH react with 1 mol H2S
Molar mass NaOH = 40g/mol
32.0g NaOH = 32/40 = 0.80 mol NaOH
This will react with 0.40 mol H2S
1000mL H2S solution = 1.5 mol H2S
volume that contains 0.4 mol H2S = 1000/1.5*0.4 = 267mL