2x+y=3
4x+2y=9
a) (2,2)
b) (2,-2)
c) no solution
d) infinite solutions on the line
4x+2y=9
a) (2,2)
b) (2,-2)
c) no solution
d) infinite solutions on the line
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c)
multiply 1st eqn by 2 and u get : 4x + 2y = 6
using the 2nd eqn and the result above u have 6 = 9 which is non-sense
thanks for the correction Alejandroid Jerkbomb --- I usually correct my answers before moving on to the next question
multiply 1st eqn by 2 and u get : 4x + 2y = 6
using the 2nd eqn and the result above u have 6 = 9 which is non-sense
thanks for the correction Alejandroid Jerkbomb --- I usually correct my answers before moving on to the next question
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2x+y=3
y=3-2x
4x+2(3-2x)=9
4x's cancel
2=9 ---it doesn't
c. No solution
Infinite solutions would exist if you got 2=2 or 9=9
@Paul you're wrong because 2(2x+y)=3(2)=6 which doesn't equal 9
y=3-2x
4x+2(3-2x)=9
4x's cancel
2=9 ---it doesn't
c. No solution
Infinite solutions would exist if you got 2=2 or 9=9
@Paul you're wrong because 2(2x+y)=3(2)=6 which doesn't equal 9
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2x + y = 3
y = 3 - 2x
4x + 2(3 - 2x) = 9
4x + 6 - 4x = 9
6 = 9
no solution
y = 3 - 2x
4x + 2(3 - 2x) = 9
4x + 6 - 4x = 9
6 = 9
no solution
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c
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c)