2NACl3>> 2NACl3 + 3 O2

12.00 moles of NACLO3 will produce how many grams of O2? how many grams if NACl are produced when 80.0 grams if O2 are produced?


Can some body please help i dont understand this problem please show me the steps.

First, you need the correct balanced equation:
2 NaClO3 → 2 NaCl + 3 O2

(80.0 g O2) / (31.9989 g O2/mol) x (2/3) x (58.4430 g NaCl/mol) = 97.4 g NaCl

2NaClO3 -------------> 2NaCl + 3O2 is the correct equation. Your equation is totally wrong.

Notice in MY equation that for every 2 moles of NaClO3 you get 3 moles of O2?

Well twelve moles of NaClO3 would give you 3/2 x 12 or 18 moles of O2

Mass = moles x Molar Mass

so mass of O2 would be 18 moles x 32 g/mol = 576 g of O2

As tot he second question, work backwards from O2. If only 80 g of O2 are produced, convert that to moles

moles of O2 = mass / Molar Mass

moles of O2 = 80 g / 32 g/mol = 2.5 moles of O2

The equation says that for every 3 mol of O2 produced you only get 2 moles of NaCl or a mol ratio of 2/3

So 2.5 mol x 2.3 = 1.667 mol of NaCl

mass of 1.667 mol of NaCl = mass x Molar Mass

mass NaCl = 1.667 mol x 58.44 g/mol = 97.4 g