Sorry, I repeated the question its just that 2 people answered something that didn't have to do with the question.
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-y > 5 - 3x
to flip the sign of Y, you have to ALSO flip the signs on the other side AND flip the arrow!
so:
y < 3x - 5
unless your "y>_5" is supposed to be "-5"
in which case it's:
y < 3x + 5
to flip the sign of Y, you have to ALSO flip the signs on the other side AND flip the arrow!
so:
y < 3x - 5
unless your "y>_5" is supposed to be "-5"
in which case it's:
y < 3x + 5
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The only answer to this will still be in terms of a variable: All are inequality and equal to, I just don't know how to write it:
3x > y + 5
y < 3x - 5
Another way to actually find answers could be to treat this as a linear combination:
3x - y = 5
Since the gcd(3, -1) = 1, and 5 is a multiple of 1, this combination has a solution.
Let a = 3 and b = -1
We can express the combination in terms of a and b as:
1 = a - 2b
5 = 5a - 10b
So our x and y values are 5 and 10, respectively.
We can also state that y can be twice the value of x and the inequality will always hold
If x is 7:
21-14 > 5
If x is 20:
60-40 > 5
3x > y + 5
y < 3x - 5
Another way to actually find answers could be to treat this as a linear combination:
3x - y = 5
Since the gcd(3, -1) = 1, and 5 is a multiple of 1, this combination has a solution.
Let a = 3 and b = -1
We can express the combination in terms of a and b as:
1 = a - 2b
5 = 5a - 10b
So our x and y values are 5 and 10, respectively.
We can also state that y can be twice the value of x and the inequality will always hold
If x is 7:
21-14 > 5
If x is 20:
60-40 > 5
-
y<_3x-5