Formula for titration calculations
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Formula for titration calculations

[From: ] [author: ] [Date: 11-12-09] [Hit: ]
-.1 M NaOH = .Using 50 mL (.05L), .05L NaOH * .......
50 ml of 0.10 M NaOH completely neutralizes .30 ml of hydrochloric acid. Calculate the concentration of HCL.

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.1 M NaOH = .1mol/L NaOH

Using 50 mL (.05L), .05L NaOH * .1 mol/L NaOH = .005 mol NaOH

If you're completely neutralizing this, that means that mols NaOH = mols HCl, therefore .005 mol NaOH = .005 mol HCl

And since you know the starting volume for HCl (.30 mL? or do you mean 30 mL?) all you have to do is convert the mL to L and divide the # of mols (.005) by that value

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Yep!

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I assume 30 ml HCl, instead of .30ml:
Molarity of HCl: (.05 * .1)/ .03 = .17 mol
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