Calculate the number of liters of hydrogen gas that oculd be prodcued by reacting by 2.50 lbs of pure magnesium metal with an excess of hydrochloric acid at STP.
Mg + 2HCl ----> MgCl2 + H2
This is what I got let me know if I am wrong and where I messed up
25lbs * 453.6g/1 lbs * 1m/24.3g * 22.4L/1m = 10453.3
Mg + 2HCl ----> MgCl2 + H2
This is what I got let me know if I am wrong and where I messed up
25lbs * 453.6g/1 lbs * 1m/24.3g * 22.4L/1m = 10453.3
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Yep, you're right! Just include my short explanation :)
Mg + 2HCl ----> MgCl2 + H2
2.5lb * 453 g = 1132.5g
1132.5 * 22.4/ 24 = 1057 litter
Mg + 2HCl ----> MgCl2 + H2
2.5lb * 453 g = 1132.5g
1132.5 * 22.4/ 24 = 1057 litter