A ball is thrown horizontally from the top of a building 45.9m high..PHYSICS Please help!!

(1/4) A ball is thrown horizontally from the top of a building 45.9m high. The ball strikes the ground at a point 121m from the base of the building. The acceleration of gravity is a 9.8m/s^2. Find the time the ball is in motion. (FOUND THE ANSWER: 3.060612184 seconds)

(2/4) Find the initial velocity of the ball. Answer in units of s.

(3/4) Find the x component of its velocity just before it strikes the ground. Answer in units of m/s.

(4/4) Find the y component of its velocity just before it strikes the ground. Answer in units of m/s.

(2/4):
Horizontal distance = initial velocity horizontally x time
121m = V x 3.06s
Initial velocity = 39.54 m/s

(3/4):
39.54 m/s
It's x component does not change if air resistance is not part of the problem.

(4/4):
Velocity = Initial velocity vertically (which is zero because it was moving horizontally) - gravity x time
V = 0 - 9.8m/s ^2 x 3.06s
V = -29.99 m/s (It is negative because velocity also has to do with direction, and the direction is down, hence the velocity must be negative

Was the heading of this question group "stupid *** physics questions?"
Was the heading of this group "I am too damn lazy to figure out my homework on my own?"
There is a gay guy on here that probably has some interesting ideas on what you can do with your ball.