FULL QUESTION: In the reaction show below if appx. 160 grams of Fe2O3 completely react with the H2 how many grams of water(H2O) will be produced?
Fe2O3 + 3H2 ---> 2Fe + 3H2O
A. 18g
B. 22g
C. 54g
D. 102g
Fe2O3 + 3H2 ---> 2Fe + 3H2O
A. 18g
B. 22g
C. 54g
D. 102g
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Fe2O3 + 3H2 --> 2Fe + 3H2O
160g / 159.6g/mole = 1mole Fe2O3
1mole Fe2O3 x (3H2O / 1Fe2O3) x 18g/mole = 54g H2O
160g / 159.6g/mole = 1mole Fe2O3
1mole Fe2O3 x (3H2O / 1Fe2O3) x 18g/mole = 54g H2O