A solution of copper (II) sulfate is added to a solution of barium hydroxide

I got this equation:
CuSO(4) + Ba(OH)2 --> Cu(OH)(2) + Ba SO(4)
Is this right? If not, what is the right answer and what is the net ionic equation?
Thanks so much!

You've got the full chemical reaction equation balanced ;
whats missing are the state symbols beside each reactant or product. The key product is the copper hydroxide, it precipitates in the reaction , leaving you in no doubt that some chemical reaction has occurred when one pours one solution into the other.

CuSO4(aq) + Ba(OH)2 (aq) --> Cu(OH)2 (s) + BaSO4 (aq)

The net ionic equation 'concentrates' on the fact that the free ions of copper and hydroxide from each solution react by binding together.

Cu2+(aq) + 2 OH- (aq) -------> Cu(OH)2 (s)

For the net equation, separate the reactants into their ions and put an (aq) next to them.

The products stay the way you wrote them, but it would be more correct to put an (s) next to them.