How can you get butanoic acid from butane

So I have to start with butane and synthesize butanoic acid a few of the following reactions: addition, elimination, oxidation, reduction, condensation, substitution and hydrolysis

this is what i have:

Step 1: (elimination?)
butane ---> 1-butene + 2-butene + hydrogen gas

Step 2: addition
1-butene + water ---> 1-butanol + 2-butanol

Step 3: oxidation
1-butanol + [O] --> butanol + hydrogen gas

Step 4: oxidation
butanal + [O] --> butanoic acid
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or should i do:

Step 1: substitution
butane + chlorine gas --> 1-chlorobutane + 2-chlorobutane + HCl

Step 2: substitution
1-chlorobutane + water --> butanol + HCl

Step 3: oxidaiton
1-butanol + [O] --> butanoic acid

im only in grade 12, so please refrain from really complicated answers.
thanks!

In your first reaction scheme, the first step - which is indeed an elimination reaction - won't work. In order to do an elimination, you need to have a good leaving group - a molecule or ion that can easily be removed. There isn't a good leaving group in butane, so you can't do an elimination reaction on it directly.

The second scheme you have will work. Alkanes (like butane) will react with halogens via a free radical mechanism to give halogenated alkanes. Halogens are good leaving groups, so replacing chlorine with water in the next step isn't a problem. In reality, you'd probably use a base - like NaOH as well. The oxidation of 1-butanol to butanoic acid is the final step, and would also work. A strong oxidizing agent, like KMnO4, would probably be used to do this.

how are you only in high school doing organic reactions, that doesnt seem likely especially when your doing carboxylic acids which is a second semester organic topic?! just curious?