The human eye can detect light at a frequency of 6.94 x 1014 Hz in the visible region of the spectrum. Calculate the energy, in joules, of an individual photon of this light.
a. 6.94E+14 J
b. 2.86E-40 J
c. 9.55E-49 J
d. 4.60E-19 J
e. 2.77E+5 J
a. 6.94E+14 J
b. 2.86E-40 J
c. 9.55E-49 J
d. 4.60E-19 J
e. 2.77E+5 J
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E(energy) = frequency *h
E = 6.94* 10^14s-1 * 6.626*10^-34 J*s=4.60 J
h is constant=6.626*10^-34J*s.It is called Planck`s constant.
Hz is be expressed by s-1 in order to cancel units .
E = 6.94* 10^14s-1 * 6.626*10^-34 J*s=4.60 J
h is constant=6.626*10^-34J*s.It is called Planck`s constant.
Hz is be expressed by s-1 in order to cancel units .