Calculate the hydronium ion concentration in 0.125M formic acid, HCHO2

Ka = 1.76x10^2- = {H+(aq)} {HCOO-(aq)} / {HCOOH(aq}
(x) (x) / 1.25x10^1-
x^2 =1.76x10^-2 X 1.25x10^-1
= 2.2x10^-3 = 22.0x10^-4
x = 4.69x10^-2 moles/L