Carbon dioxide and water vapor are produced when octane (O8H18) combusts. How many grams of Octane must be combusted in excess oxygen to generate 855g of CO2?
I have other problems like this and need to learn how to do it not just get the answer. If someone could walk me through the general question without specific answers it would be much appreciated.
I have other problems like this and need to learn how to do it not just get the answer. If someone could walk me through the general question without specific answers it would be much appreciated.
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When solving this and other types of chemistry problems, it is often useful to write down the chemical reactions. For this problem, you would have to write down the reaction because it is necessary to find the stoichiometric coefficients.
You are given the final mass of one of the products. From this, you can find the number of moles produced of that product. If we suppose that:
1A --> 3B, we know for every 1 mole of A, we will end up with 3 moles of B.
For your problem, you would apply the same logic. Hope this helps!
You are given the final mass of one of the products. From this, you can find the number of moles produced of that product. If we suppose that:
1A --> 3B, we know for every 1 mole of A, we will end up with 3 moles of B.
For your problem, you would apply the same logic. Hope this helps!
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2 C8H18 + 25 O2 → 16 CO2 + 18 H2O
(855 g CO2) / (44.0096 g CO2/mol) x (2/16) x (114.2293 g C8H18/mol) = 277 g C8H18
(855 g CO2) / (44.0096 g CO2/mol) x (2/16) x (114.2293 g C8H18/mol) = 277 g C8H18