Calculate the osmotic pressure (in atm) of 8 L of an aqueous solution with a concentration of 0.1073 M at 29.1°C, if the solute concerned is totally dissociated in three ions ( i.e. it could be MgCl 2 or Na 2SO 4)
Thanks!
Thanks!
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The osmotic pressure for dilute solutions can be found using the Morse Equation.
P = i*M*R*T
where
i = Van't Hoff factor
M = molarity of the solution
R = universal gas constant
T = absolute temp ºK
For an ionic solution (electrolyte) i = 1
R = 0.0821 L*atm/(ºK-mol)
M = 0.1073
then
P = 0.1073*0.0821*(273.16 + 29.1) = 2.66 atm
P = i*M*R*T
where
i = Van't Hoff factor
M = molarity of the solution
R = universal gas constant
T = absolute temp ºK
For an ionic solution (electrolyte) i = 1
R = 0.0821 L*atm/(ºK-mol)
M = 0.1073
then
P = 0.1073*0.0821*(273.16 + 29.1) = 2.66 atm