How do I balance this equatiom
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How do I balance this equatiom

[From: ] [author: ] [Date: 11-09-24] [Hit: ]
......
H2S + CO -----> CH3CO2H + S8

And please explain it to me! Thanks!

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The answer by M has a spurious factor of 4 in it. Here's the correct answer:

Balance the H and the S at the same time:

2H2S + CO -----> CH3CO2H + (1/4)S8

Balance the C and the O at the same time:

2H2S + 2CO -----> CH3CO2H + (1/4)S8

Clear the fraction:

8H2S + 8CO -----> 4CH3CO2H + S8

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32H2S + 32CO -----> 16CH3CO2H + 4S8
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