moles of Ag = .005792
moles of O = .005066
molar ratio Ag : O = 57.92 : 50.66
divide by the smallest we get Ag : O = 1.143 : 1
multiply by 7
Ag : O = 8 : 7
compound is Ag8O7
moles of O = .005066
molar ratio Ag : O = 57.92 : 50.66
divide by the smallest we get Ag : O = 1.143 : 1
multiply by 7
Ag : O = 8 : 7
compound is Ag8O7