Calculate the cell potential at 25 degrees Celsius based upon the overall reaction:
3Fe 3+(aq) + Al(s) => 3Fe (aq) + Al 3+ (aq)
if [Fe 3+] = 0.300 M, [Fe 2+] = 0.150 M, and [Al 3+] = 0.300 M. The standard reduction potentials are as follows:
Fe 3+ (aq) + e- => Fe 2+ E^o = +0.771 V
Al 3+ (aq) + 3e- => Al (s) E^o = -1.66 V
3Fe 3+(aq) + Al(s) => 3Fe (aq) + Al 3+ (aq)
if [Fe 3+] = 0.300 M, [Fe 2+] = 0.150 M, and [Al 3+] = 0.300 M. The standard reduction potentials are as follows:
Fe 3+ (aq) + e- => Fe 2+ E^o = +0.771 V
Al 3+ (aq) + 3e- => Al (s) E^o = -1.66 V
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