(Part 1 of 3)
If 5.96 mol of ethane (C2H6) undergo combustion according to the unbalanced equation
C2H6 + O2 −> CO2 + H2O,
how much oxygen is required?
Answer in units of mol.
(Part 2 of 3)
How much CO2 is formed?
Answer in units of mol.
(Part 3 of 3)
How much H2O is formed?
Answer in units of mol.
If 5.96 mol of ethane (C2H6) undergo combustion according to the unbalanced equation
C2H6 + O2 −> CO2 + H2O,
how much oxygen is required?
Answer in units of mol.
(Part 2 of 3)
How much CO2 is formed?
Answer in units of mol.
(Part 3 of 3)
How much H2O is formed?
Answer in units of mol.
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First, let's balance the equation. You may use the electron balance method, but since it's hard to write this here, I'll just balance it. Here we go:
2C2H6 + 7O2 -> 4CO2 + 6H2O
Let's see the molar proportions:
2 mol ethane react with 7 mol oxygen
5.96 mol -> x mol oxygen
Solve for x: x=5.96*7/2=20.86 mol O2
We do the same with the other two:
2 mol C2H6 -> 4 mol CO2
5.92 mol -> x mol CO2
x=5.92*4/2=11.84 mol CO2
2 mol C2H6 -> 6 mol H2O
5.92 mol -> x mol H2O
x=5.92*6/2=17.76 mol H2O
I didn't explain much but I hope you did understand me :)
2C2H6 + 7O2 -> 4CO2 + 6H2O
Let's see the molar proportions:
2 mol ethane react with 7 mol oxygen
5.96 mol -> x mol oxygen
Solve for x: x=5.96*7/2=20.86 mol O2
We do the same with the other two:
2 mol C2H6 -> 4 mol CO2
5.92 mol -> x mol CO2
x=5.92*4/2=11.84 mol CO2
2 mol C2H6 -> 6 mol H2O
5.92 mol -> x mol H2O
x=5.92*6/2=17.76 mol H2O
I didn't explain much but I hope you did understand me :)