Chem: Heisenberg uncertainty principle help
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Chem: Heisenberg uncertainty principle help

[From: ] [author: ] [Date: 11-05-10] [Hit: ]
05 * 10^4 m/s with an uncertainty of 0.10 * 10^4 m/s?the answer is 0.31 Angstrom, but i dont know how to get that. please explain!......
The Heisenberg uncertainty principle is written Δx*mΔu ≥ h/(4π).
what is the minimum uncertainty in position (in Angstrom) of a hydrogen atom traveling at 1.05 * 10^4 m/s with an uncertainty of 0.10 * 10^4 m/s?

the answer is 0.31 Angstrom, but i dont' know how to get that. please explain!

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Hey half the work has been done by the equation the uncertainty in position means you have to calculate Δx and for Δv take original -uncerianity value
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