find the mass of 350 ml of nh3 at 0.921 atm & 27C and also tell me what you did to get the answer. thanks :)
-
PV=nRT
(0.921atm) (0.35L) = n (0.08206) (300.15K)
0.3224 = n (24.63)
0.0131 = n
0.0131 times 17g= 0.2227 grams of NH3
R is a constant, n is the number of moles, 17 grams is the molar mass of NH3.
(0.921atm) (0.35L) = n (0.08206) (300.15K)
0.3224 = n (24.63)
0.0131 = n
0.0131 times 17g= 0.2227 grams of NH3
R is a constant, n is the number of moles, 17 grams is the molar mass of NH3.