Can somebody help me with a chem equation problem
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Can somebody help me with a chem equation problem

[From: ] [author: ] [Date: 11-05-10] [Hit: ]
35L) = n (0.08206) (300.0.3224 = n (24.0.0.......
find the mass of 350 ml of nh3 at 0.921 atm & 27C and also tell me what you did to get the answer. thanks :)

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PV=nRT
(0.921atm) (0.35L) = n (0.08206) (300.15K)
0.3224 = n (24.63)
0.0131 = n
0.0131 times 17g= 0.2227 grams of NH3

R is a constant, n is the number of moles, 17 grams is the molar mass of NH3.
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