Can you solve this integral!
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Can you solve this integral!

[From: ] [author: ] [Date: 11-05-09] [Hit: ]
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Integral from 0 to 1 of: 6x(sqrt(1 + x^2))

show steps please, thank you

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∫ 6x√(1 + x²) dx = 6 ∫ x√(1 + x²) dx = 3 ∫ u√u du = 2 √u³ + C = 2√(x² + 1)³ + C

[substitution u=1+x² was used]


1
∫ 6x√(1 + x²) dx = 2√(1² + 1)³ - 2 √(0² + 1)³ = 4√2 - 2 = 3.657
0

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1
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