I have 2 questions: m²+5m=0
and d²-21d=0
Thanks & explain! :}
and d²-21d=0
Thanks & explain! :}
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m(m+5) = 0
m+5=0/m
m+5 =0
m = - 5
d( d- 21) = 0
d -21 = 0
d = 21
m+5=0/m
m+5 =0
m = - 5
d( d- 21) = 0
d -21 = 0
d = 21
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For real this is 10th grade stuff? Where I`m at we get this in the 7th grade! Anyway, here`s the solution:
m1+m2=-5
m1*m2=0
m1=-5
m2=0
d1+d2=21
d1*d2=0
d1=21
d2=0
m1+m2=-5
m1*m2=0
m1=-5
m2=0
d1+d2=21
d1*d2=0
d1=21
d2=0
-
m(m+5)=0 m=0 or m+5=0
m=0 or m=-5
d(d-21)=0 d=0 or d-21=0
d=0 or d=21
if you multiply the number before the parantes you will get your first equation
m=0 or m=-5
d(d-21)=0 d=0 or d-21=0
d=0 or d=21
if you multiply the number before the parantes you will get your first equation
-
m(m+5)=0 so either m=0 or m+5=0
solutions: m=0 and m=-5
d(d-21)=0, m=0 and m=21
solutions: m=0 and m=-5
d(d-21)=0, m=0 and m=21