A body is projected form a certain height horizontally and reaches the ground in 6.2 seconds. Find the resultant velocity.
I found the height: 188 m
Range: 150 m
How to find the resultant velocity
I found the height: 188 m
Range: 150 m
How to find the resultant velocity
-
Range: 150
time: 6.2s
Therefore:
Horizontal velocity= s/t =150/6.2 = approx. 24.2m.s^-1
Vertical velocity: v0 + at = 0+ 9.8*6.2= 60.76m.s-1
Theeeeen draw a diagram with horizontal and vertical components, use pythag to find the hypotenuse (resulting velocity) which should be 65.4ms-1 then finally find the angle using one of the trig formulas.
time: 6.2s
Therefore:
Horizontal velocity= s/t =150/6.2 = approx. 24.2m.s^-1
Vertical velocity: v0 + at = 0+ 9.8*6.2= 60.76m.s-1
Theeeeen draw a diagram with horizontal and vertical components, use pythag to find the hypotenuse (resulting velocity) which should be 65.4ms-1 then finally find the angle using one of the trig formulas.