First part: find the orbital speed for a lunar probe that is in a circular orbit 663 km above these race of the moon?
I got this one right it's square root[(6.67*10^-11)(7.35*10^22)/2373000)
=1.44*10^3m/s
Now I need help!!!calculate the period in minutes?
Howwww!?
I got this one right it's square root[(6.67*10^-11)(7.35*10^22)/2373000)
=1.44*10^3m/s
Now I need help!!!calculate the period in minutes?
Howwww!?
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It would help you if you knew the definition of a period.
A period is the time it takes to go one cycle; in your case, once around the Moon. Once around is a cycle.
At V = 1.44E3 mps, the time to go once around is T = 2piR/V where 2piR is the circumference (once around) of that orbit R = h + r where h = 663 km and r is the radius of the Moon.
Look up the Moon's radius and find R in meters. Plug that into the T equation along with the V you found and you'll have T in seconds. There are 60 seconds in a minute; convert T in seconds into minutes using that 60 s/min conversion. And there you are.
A period is the time it takes to go one cycle; in your case, once around the Moon. Once around is a cycle.
At V = 1.44E3 mps, the time to go once around is T = 2piR/V where 2piR is the circumference (once around) of that orbit R = h + r where h = 663 km and r is the radius of the Moon.
Look up the Moon's radius and find R in meters. Plug that into the T equation along with the V you found and you'll have T in seconds. There are 60 seconds in a minute; convert T in seconds into minutes using that 60 s/min conversion. And there you are.
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Divide it by 60.