A block is placed on a plane whose angle of inclination is 30º. The coefficients of static
and kinetic friction for the block on the inclined plane are both 0.2. The block
A) remains stationary on the inclined plane.
B) accelerates down the inclined plane.
C) travels down the inclined plane at constant velocity.
D) travels up the inclined plane at constant velocity.
E) accelerates up the inclined plane.
______________________________________…
The Answer is B and I was able to solve for that answer, but I just want to check if my reasoning is correct because the fact that the mass was taken out confused me a bit..
Fparrallel=mgsinΘ
ma=mgsinΘ
a2=-gsinΘ
Fk=µmgcosΘ
ma=µmgcosΘ
a1=µgcosΘ
a2+a1
-gsinΘ+µgcosΘ
-(9.8)sin30+(0.2)(9.8)cos30
= -3.20 m/s^2 there I conclude that it accelerates downward.
and kinetic friction for the block on the inclined plane are both 0.2. The block
A) remains stationary on the inclined plane.
B) accelerates down the inclined plane.
C) travels down the inclined plane at constant velocity.
D) travels up the inclined plane at constant velocity.
E) accelerates up the inclined plane.
______________________________________…
The Answer is B and I was able to solve for that answer, but I just want to check if my reasoning is correct because the fact that the mass was taken out confused me a bit..
Fparrallel=mgsinΘ
ma=mgsinΘ
a2=-gsinΘ
Fk=µmgcosΘ
ma=µmgcosΘ
a1=µgcosΘ
a2+a1
-gsinΘ+µgcosΘ
-(9.8)sin30+(0.2)(9.8)cos30
= -3.20 m/s^2 there I conclude that it accelerates downward.
-
The net acceleration down the plane is
a = g(sinΘ - µcosΘ) = 3.20 m/s² downward
The mass is irrelevant because any mass with that Cf will have the same acceleration
a = g(sinΘ - µcosΘ) = 3.20 m/s² downward
The mass is irrelevant because any mass with that Cf will have the same acceleration
-
You are correct.