A science student riding on a flatcar of a train moving at a constant speed of 5.8 m/s throws a ball toward the caboose along a path that the student judges as making an initial angle of 53° to the horizontal. The teacher, who is standing on the ground nearby, observes the ball rising vertically. How high does the ball rise?
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Horizontal component of ball velocity is same as train, = 5.8m/sec.
Initial vertical component = (tan 53) x 5.8, = 7.69m/sec.
Height observed to rise = (v^2/2g) = 3 metres above release.
Initial vertical component = (tan 53) x 5.8, = 7.69m/sec.
Height observed to rise = (v^2/2g) = 3 metres above release.