A wooden block slides downs 28 degree incline with acceleration 3.85 m/s^2. How do you find the coefficient of kinetic friction?
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Fnet = Fg parallel - Ff
Fnormal = mg cos theta
ma = (mg sin theta) - mu (mg cos theta)
* note that the m's cancel out
a = g sin theta - mu g cos theta
a = 3.85
g = 9.81
theta = 28 deg
solve for mu
Fnormal = mg cos theta
ma = (mg sin theta) - mu (mg cos theta)
* note that the m's cancel out
a = g sin theta - mu g cos theta
a = 3.85
g = 9.81
theta = 28 deg
solve for mu