A ball is projected upwards with velocity of 100m/s. Find the speed of ball at half the max. height.
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By v^2 = u^2 - 2gh
=>0 = (100)^2 - 2gH
=>H = 10000/2g meter
Let the velocity at height(h) = 5000/2g meter is v m/s
=>again by :- v^2 = u^2 - 2gh
=>v^2 = (100)^2 - 2g x 5000/2g
=>v = √5000
=>v = 70.71 m/s
=>0 = (100)^2 - 2gH
=>H = 10000/2g meter
Let the velocity at height(h) = 5000/2g meter is v m/s
=>again by :- v^2 = u^2 - 2gh
=>v^2 = (100)^2 - 2g x 5000/2g
=>v = √5000
=>v = 70.71 m/s