Two geekie physics students with a combined mass of 132 kg jump into their old car to run out for some late night pizza. The distance between the front and back axles of the car is 2.6 m. When they get in the car, the springs compress a total of 9.1 cm. On their way to the Pizza Hut, when they go over a bump, the car oscillates up and down with a period of 1.6 seconds.
(a) What is mass of the car?
I tried doing mg=-k(change in x) and I got K=14229.89, then I did T=2pi sqroot(m+132/14229.89) and solved for m and got 5797.9 but that's not right. I don't know what other equation to use or if I'm missing a step, can someone help me?
(a) What is mass of the car?
I tried doing mg=-k(change in x) and I got K=14229.89, then I did T=2pi sqroot(m+132/14229.89) and solved for m and got 5797.9 but that's not right. I don't know what other equation to use or if I'm missing a step, can someone help me?
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If T = 2 pi() sqrt( m/k)
then T / ( 2pi() ) = sqrt ( m/k)
(T / (2 pi() ) ^2 * k = m ( where m is the total mass )
using this I don't get your answer. I got a total mass of only 920 kg approx.
(1.6 / ( 2*pi() )) ^ 2 * 14.2 * 10 ^ 3 = 920 kg total.
then T / ( 2pi() ) = sqrt ( m/k)
(T / (2 pi() ) ^2 * k = m ( where m is the total mass )
using this I don't get your answer. I got a total mass of only 920 kg approx.
(1.6 / ( 2*pi() )) ^ 2 * 14.2 * 10 ^ 3 = 920 kg total.