Physics question of going from Ek to Distance.

1. A dim but resourceful student has a summer job in a factory moving boxes. The 50 kg student finds that if he runs at a speed of 5.8 m/s and then dives head first into the boxes, he can move them across the floor. If the boxes have a mass of 65 kg and the force of friction between the boxes and the floor is 382 N, how far will he move the boxes after hitting it six times?

First I will find the amount of energy the student is using
Ek=mv^2/2
m=50kg
v=5.8m/s
Ek=841 J

Now I will find out how far the box moved.
d=w/F
d=841 J/382N
d=2.2m
He uses 841J of force, with that he has to overcome 382N of friction he pushes the box 2.2m.

2.2m * 6= 13.2m. He pushes the box 13.2m.

I DID IT RIGHTTTT? Right?... I hate being so anxious.

I don't see anything wrong except it is an INELASTIC collision and energy is not conserved. It all depends what the stupid student does after the collision. Is he stuck on the box?? Does he bounce off?? If he sticks on then you can use the conservation of momentum to find the final; velocity and then energy, and find d just as you did. If he bounces off you need to know what velocity he bounces off at??. You are probably correct if you haven't covered momentum yet. It is a good sign that you think there might be something wrong. That is one of the hardest things Physics people have to learn and never forget. I think you're OK. At least you're smarter than the student with the headache !!