A 20,000kg railroad car travels down the track at 80m/s and hits a second railroad car of 20,000kg, the cars become coupled and continuing traveling calculate the final velocity of the cars
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Conservation of momentum: M1V1 + M2V2 = M3V3
Since the second railroad car is initially at rest, V2 = 0 m/s
M3 = the mass of the first car + the mass of the second car = 40,000 kg
(20,000)(80) + (20,000)(0) = (40,000)V3
V3 = 40 m/s
Since the second railroad car is initially at rest, V2 = 0 m/s
M3 = the mass of the first car + the mass of the second car = 40,000 kg
(20,000)(80) + (20,000)(0) = (40,000)V3
V3 = 40 m/s
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Gg