HELP WITH PHYSICS QUESTION.
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HELP WITH PHYSICS QUESTION.

[From: ] [author: ] [Date: 12-05-02] [Hit: ]
000kg,Since the second railroad car is initially at rest,M3 = the mass of the first car + the mass of the second car = 40,(20,000)(80) + (20,000)(0) = (40,......
A 20,000kg railroad car travels down the track at 80m/s and hits a second railroad car of 20,000kg, the cars become coupled and continuing traveling calculate the final velocity of the cars

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Conservation of momentum: M1V1 + M2V2 = M3V3

Since the second railroad car is initially at rest, V2 = 0 m/s
M3 = the mass of the first car + the mass of the second car = 40,000 kg

(20,000)(80) + (20,000)(0) = (40,000)V3

V3 = 40 m/s

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