There are 100 people in a population. All 100 people can become invisible at will. Invisibility is a dominant trait (I) and 40 people are heterozygous for this train (Ii).
a.)What are the genotypes of the original population with the number of individuals with each genotype?
b.)What is the frequency for the dominant allele I?
c.)What is the frequency of the recessive allele i, in this population?
thanks! show work please!
a.)What are the genotypes of the original population with the number of individuals with each genotype?
b.)What is the frequency for the dominant allele I?
c.)What is the frequency of the recessive allele i, in this population?
thanks! show work please!
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This is a math question and has nothing to do with Hardy-Weinberg.
a.)What are the genotypes of the original population with the number of individuals with each genotype?
There are a total of 100 individuals (given) all of whom can become invisible.
40 are Ii (given)
60 are II (subtracted 40 from 100)
b.)What is the frequency for the dominant allele I?
There are 100 people (given) which means 200 alleles.
From the heterozygotes there are 40 I alleles.
From the homozygotes there are 2 * 60 = 120 alleles.
So, that's a total of 120 + 40 I alleles = 160 I alleles.
The frequency is 160/200 = 0.8 = 80% (answer)
c.)What is the frequency of the recessive allele i, in this population?
100% - 80% = 20% (answer)
a.)What are the genotypes of the original population with the number of individuals with each genotype?
There are a total of 100 individuals (given) all of whom can become invisible.
40 are Ii (given)
60 are II (subtracted 40 from 100)
b.)What is the frequency for the dominant allele I?
There are 100 people (given) which means 200 alleles.
From the heterozygotes there are 40 I alleles.
From the homozygotes there are 2 * 60 = 120 alleles.
So, that's a total of 120 + 40 I alleles = 160 I alleles.
The frequency is 160/200 = 0.8 = 80% (answer)
c.)What is the frequency of the recessive allele i, in this population?
100% - 80% = 20% (answer)