Math help????????????????
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Math help????????????????

[From: ] [author: ] [Date: 12-05-02] [Hit: ]
2 , 0) and (-4.8 , 0).......
how do you do this..

approximate the zeros of the function to the nearest tenth

f(x)= x^2 + 5x +1

-
Finding the zeroes means finding the roots of the function.

0 = x^2+5x+1

Quadratic Formula:
x = -b+-√(b^2-4ac) / 2a

In this problem: a=1, b=5, and c=1.

x = -(5)+-√((5)^2-4(1)(1)) / 2(1)
x = -5+-√(25-4) / 2
x = -5+-√21 / 2

Answer: The point ( (-5+√21)/2 , 0 ) and the point ( (-5-√21)/2 , 0 ).
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EDIT: ...which to the nearest tenth is (-0.2 , 0) and (-4.8 , 0).
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