Kinetic=potential energy problem

I don't know why this problem is equal to 2.8 m/s...

a 1kg flashlight falls to the floor from height 0.8m. at the point during its fall, when its potential energy exactly equals its kinetic energy, How fast is it moving?

I thought it would be 3.8m/s, but I got that wrong :/

can you tell me why it's 2.8m/s? and let me know if I'm forgetting some law?

thanks!

Given,
height, h=0.8m
g=9.8m/s^2
mass, m=1kg

so,when it is on the top height it's potential energy was= m*g*h=1*9.8*0.8=7.84

so,In all the ways of falling the sum of potential & kinetic energy will be 7.84.

I mean potential energy+kinetic energy=7.84 will be always same.

now, when its potential energy exactly equals its kinetic energy,
there kinetic energy=7.84/2 [because there potential energy is equal to kinetic energy]
0.5*m*v^2=3.92
so,v=2.8(ans)

Potential energy at 0.8m is Wp=9.8m/s^2 * 1kg * 0.8m = 7.84J This is also total energy because kinetic energy at this point is zero!
When potential energy is equal to kinetic energy the potential energy is half the total energy because total energy = potential + kinetic. So when kinetic is equal to potential it is Wp/2=3.29J
I think you know kinetic energy is Wk=(m*v^2)/2 so simply express v from here and since Wk=Wp/2 that is peace of cake. v=sqrt(Wp)=2.8m/s

Perhaps you forgot the role of airfriction?