Alright, on an unknown planet Kamina decided he want's to challenge the leader of the beastmen to a duel. The beastment have a huge mecha that weighs about 4million tons. Kamina says "Just who the hell do you think I am?" and decides to use a crossover trait from goku and unleashes a kamehameha that sends the giant mecha flying into outer space. If the distance of the mecha traveled through space is approx. 900,385,119 light years in the matter of 50.0 seconds, then what is the velocity at which the mecha was sent flying? How much force was behind the kamehameha?
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newton second law: Force=mass*acceleration
so we need acceleration
we have: final velocity= initial vel. +acc.*time
as the mecha's initial velocity is zero then: fv=a*t
which is: distance/time used =a*t
we take as a final time t= time used
so we get : a=d/t²
so Force=m*d/t²
=4*10^6*1000 * 900385119*9.46*10^15 /(50)² (i converted lightyears in meters)
so force=1.3628229161184×10^31 N
the velocity is: V=d/t=900385119*9.46*10^15/50
V=1.703528645148×10^23 m/s
which is a crazy speed, as it is more than 5*10^14 times the speed of light
so we need acceleration
we have: final velocity= initial vel. +acc.*time
as the mecha's initial velocity is zero then: fv=a*t
which is: distance/time used =a*t
we take as a final time t= time used
so we get : a=d/t²
so Force=m*d/t²
=4*10^6*1000 * 900385119*9.46*10^15 /(50)² (i converted lightyears in meters)
so force=1.3628229161184×10^31 N
the velocity is: V=d/t=900385119*9.46*10^15/50
V=1.703528645148×10^23 m/s
which is a crazy speed, as it is more than 5*10^14 times the speed of light