I know generally you cannot square root a negative number, so here's my question, what if the question looks something like this:
(sqrt(3(0)-9))^2
You would end up with a sqrt -9, however, the sqrt is in brackets to a power of 2.
I just want to know the order in which you should approach this problem?
With BEDMAS, you have to do brackets first, but since you can't sqrt, how do you solve this? Do you just skip doing the brackets and do the exponent to cancel out the sqrt?
I would just like to know the proper math order and rules you use to solve this.
(sqrt(3(0)-9))^2
You would end up with a sqrt -9, however, the sqrt is in brackets to a power of 2.
I just want to know the order in which you should approach this problem?
With BEDMAS, you have to do brackets first, but since you can't sqrt, how do you solve this? Do you just skip doing the brackets and do the exponent to cancel out the sqrt?
I would just like to know the proper math order and rules you use to solve this.
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Think of a sqrt as just a thing raised to the 1/2 power. Therefore it is (-9^(1/2))^2. So you do parentheses first, and multiply the exponents to get -9^1 which is simply -9.