What is the molar concentration of a saturated solution of calcium hydroxide that contains 0.140 g of solute in 350.0 mL of solution?
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Molar concentration is (moles of solute)/(liters of solution), so:
Molar mass of calcium hydroxide is: 74.093 g/mol
Moles of calcium hydroxide sample is: 0.140g/74.093g/mol = 0.00189 mols
Liters of solution: 350.0 mL/ 1000 mL = 0.3500 L
Molar concentration is: (0.00189 mols of calcium hydroxide)/(0.500 L of solution) = 0.00540 M
Edit: Sid is correct except for significant figures, there should be 3 SF.
Molar mass of calcium hydroxide is: 74.093 g/mol
Moles of calcium hydroxide sample is: 0.140g/74.093g/mol = 0.00189 mols
Liters of solution: 350.0 mL/ 1000 mL = 0.3500 L
Molar concentration is: (0.00189 mols of calcium hydroxide)/(0.500 L of solution) = 0.00540 M
Edit: Sid is correct except for significant figures, there should be 3 SF.
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Molecular Mass of Calcium Hydroxide = 40 + 32 + 2 = 74
moles of Ca(OH)2 = 0.140/74 = 1.89x10^-3
Molarity = Moles/volume
Molarity = 1.89x10^-3/350*1000 = 5.4x10^-3 M
moles of Ca(OH)2 = 0.140/74 = 1.89x10^-3
Molarity = Moles/volume
Molarity = 1.89x10^-3/350*1000 = 5.4x10^-3 M