PLEASE!! can someone solve these three simple vector questions for me

I don't know anything about vectors can you please help

http://www.flickr.com/photos/69133481@N05/

EDIT: I am not going to go through and do that again using the law of sines and cosines...lol, so much work.

These are the two laws...everything you need is at the beginning of the articles.
http://en.wikipedia.org/wiki/Law_of_sine…
http://en.wikipedia.org/wiki/Law_of_cosi…

Just use the properties of complementary angles,180 degrees in a triangle, and the sine/cosine equalities for right triangles to find the specific values to plug in, and then plug and chug.

Original:

1. We start by breaking the vectors into x and y components. We can add these components together to get the third vector's components, and from that information we can determine its length. This is all done using trigonometry.

First, by observation, the second vector has a 21 m/s x component as it is moving completely horizontally, with 0 y component.

To break the second vector into components, imagine that it is the hypotenuse of a right triangle. Given one of the other angles, we can find the legs (components) of the vector using the trigonometric identities...

sin x = length of opposite side/length of hypotenuse
cos x = length of adjacent side/length of hypotenuse

In the diagram, we can see that one of the angles of the triangle would be 51 degrees. The adjacent side to that angle would be the y component, while the opposite side is the x component, so we do some simple algebra...

cos 51° = y comp/25 m/s
y comp = 15.7330098 m/s

sin 51° = x comp/25 m/s
x comp = 19.428649 m/s

We can then adding up the corresponding components of the two vectors to get the components of the third.

21 m/s + 19.428649 m/s = 40.428649 m/s = x
0 + 19.428649 m/s = 19.428649 m/s = y

Then, if we take these components to be the legs of a triangle, by the pythagorean theorem...