Mutual inductance between two pairs of coils is 5 H. A current of 10 A flowing through one coil is cut off in 0.5 s. Calculate the emf induced in the other coil.
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The current decreases from 10 A to 0 A.
dI = 0 – 10 = - 10 A
e = - M dI/dt = - 5* (-10 / 0.5) = 100 V
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dI = 0 – 10 = - 10 A
e = - M dI/dt = - 5* (-10 / 0.5) = 100 V
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